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0.24x^2-4x=9.6
We move all terms to the left:
0.24x^2-4x-(9.6)=0
We add all the numbers together, and all the variables
0.24x^2-4x-9.6=0
a = 0.24; b = -4; c = -9.6;
Δ = b2-4ac
Δ = -42-4·0.24·(-9.6)
Δ = 25.216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{25.216}}{2*0.24}=\frac{4-\sqrt{25.216}}{0.48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{25.216}}{2*0.24}=\frac{4+\sqrt{25.216}}{0.48} $
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